Question

Ria has ₹42 in the form of 50 paise and 25 paise coins. She has twice the number of 25 paise coins than 50 paise coins. How many coins of each kind

Answer 1

Given that ria has 42rs
or 42×100=4,200paise.

Let ria has x number of coins of 25 paise and y number of coins of 50 paise. Also she has twice as many 25 paise coins as she has 50 paise coins.

Therefore ,  x = 2y  --------------------------> 1.

Also the total paise =4200 paise
=> 25x + 50y = 4200
Dividing the equation by 25 we get
=> x + 2y = 108 ---------------> 2. 
put value of x from 1.in 2.

=>2y+2y=108
=>4y=108
=>y=108/4=42

Therefore, x = 2y = 2 x 42 =84

Hence ria have 84 coins of 25 paise and 42 coins of 50 paise..

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Answer 2

Answer:

Step-by-step explanation:x = 40(corresponding angles)

in ∆ ABC

angle B + angle A + angle C =180°

=> 40 + 35 + z=180

=>z = 105

z=y(corresponding angles)

so

x = 40

y = 105

z = 105