Question

Ribose has the formula C5H10O5. What is the mass of a sample containing 1.2*10^24 Carbon atoms?

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Answer 1

Heya....

1 mole of this carbon compound contain 5*Na no. of carbon atoms.

Thus, by unitary method.

1 mole = 30 * 10^23

X mole = 1.2 * 10^24

Thus, from > X = 4/10

And molecular mass of compound is 12*5+10*1+16*5 = 150 .

Thus, mass in 4/10 = 4/10*150 = 60gm...!!

Hope this will help you!! : )

Answer 2

Hey brother will you plz help me ????

Molecular mass = ( 12 g * 5 )(for C atom ) + ( 1 g * 10 )( for H atom ) + ( 16 g * 5 )( for O atom )

= 150 g

Number of moles of carbon atoms in the sample you have = number of atoms / Avagadro number

= ( 1 . 2 * 10^24 ) / ( 6 . 02 * 10^23)

= 2 moles ( approx )

So

1 mole organic compound contains 5 mole C atom

1 / 5 mole organic compound contains 1 mole C atom

2 / 5 mole organic compound contains 2 mole C atom

Mass of 1 mole organic compound = 150 g

Mass of 2 / 5mole organic compound = 150 g * ( 2 / 5 )

= 60 g