Question

rice each expression x^2-5x-6​

Answer 1

Given equation,

$x^{2} -5x+6=0$

Solving it, we get,

$x^{2} -6x+x+6=0\\=> x(x-6)+1(x+6)=0$

$=> (x + 1)(x - 6)=0$

∴ ( x + 1 ) ( x - 6 )  = 0 is the factorized expression.

                                                     

Answer 2

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$\boxed{ \fbox{ \purple{ \green{solution}}}} \large$

$x^{2}-6x+x+6=0$

=>x(x−6)+1(x+6)=0

=> (x + 1)(x - 6)=0

( x + 1 ) ( x - 6 ) = 0

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hops this may help you

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