Question

Rich and Poor: Opportunities and Challenges in an Age of Disruption

Answer 1

Answer:

Explanation:

Jim Yong Kim, President of the World Bank Group, spoke about how before 1800 everybody was poor and lived in poverty. He referred to the young people now who may not own a smart phone, but who have access to smart phones. By 2025, as many analysts are saying, the entire world will have access to broadband. He examined three ways to end extreme poverty, that is, people living under 1.90 US dollars a day, by 2030. First, focus on inclusive, sustainable economic growth. Second, focus on fostering resilience to pandemics, climate change, refugees, fragility, conflict, and violence. Third, invest more and more effectively in people.

Answer 2

Answer:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(32t2 - 64t) - 64 = 0

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 9t2-64t-64

The first term is, 9t2 its coefficient is 9 .

The middle term is, -64t its coefficient is -64 .

The last term, "the constant", is -64

Step-1 : Multiply the coefficient of the first term by the constant 9 • -64 = -576

Step-2 : Find two factors of -576 whose sum equals the coefficient of the middle term, which is -64 .

-576 + 1 = -575

-288 + 2 = -286

-192 + 3 = -189

-144 + 4 = -140

-96 + 6 = -90

-72 + 8 = -64 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -72 and 8

9t2 - 72t + 8t - 64

Step-4 : Add up the first 2 terms, pulling out like factors :

9t • (t-8)

Add up the last 2 terms, pulling out common factors :

8 • (t-8)

Step-5 : Add up the four terms of step 4 :

(9t+8) • (t-8)

Which is the desired factorization

Equation at the end of step

2

:

(t - 8) • (9t + 8) = 0

STEP

3

:

Theory - Roots of a product

3.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.