Math, asked by holadimeji74, 3 months ago

Richard works at an ice cream shop. Regular cones get two scoops of ice cream; large cones get three scoops. One hot Saturday, Richard scooped 234 regular cones and 156 large cones. One scoop of ice cream is 3 ounces. A tub of ice cream weighs 10 pounds. How many tubs of ice cream did Richard use to make the cones?
Use the conversion 1 pound = 16 ounces.

Answers

Answered by 916817178
1

Answer:

The total number of scoops of ice cream that Richard got from the tub is,

  (234 regular cones) x (2 scoops / 1 regular cone) + (156 large cones) x (2 scoops / 1 large cone) = 936 scoops

Given that each scoop weighs 3 ounces, the total weight of the ice cream is 2808 ounces. For the number of tubs,

         (2808 ounces) x (1 lb / 16 ounces) x (1 tub /10 lb) = 17.55

Thus, the answer is 18. 

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Step-by-step explanation:

Answered by NirmalPandya
0

Given:

No. of scoops for a regular cone = 2

No. of scoops for a large cone = 3

No. of regular cones sold out = 234

No. of large cones sold out = 156

Weight of a tub of ice cream = 10lb

Weight of 1 ice cream scoop = 3oz

To find:

No. of ice cream tubs required by Richard.

Solution:

Richard sells out 234 regular cones which contain 2 scoops each.

Thus, No. of scoops for 234 regular cones = 2*234=468 scoops

He also sells out 156 large cones which contain 3 scoops each.

Hence, no. of scoops for 256 large cones = 3*156=468 scoops

Total no. of scoops Richard sold = 468+468=936 scoops

Given that,

1 scoop = 3oz

1 pound = 16 oz

To convert 936 scoops to required ounces, multiply 936 with 3

∴ 936 scoops = 936*3=2808 oz

To convert 2808 oz into pounds, divide 2808 by 16

2808 oz = \frac{2808}{16}=175.5 lb

Hence, Richard requires 175.5 lb of ice cream to sell on a hot Saturday.

Also, given that one tub of ice cream weighs 10 lb. Let x be the no. of ice cream tubs required by Richard. One tub can contain 10 lb of ice cream, so 175.5 lb of ice cream can contain in x no. of tubs which is obtained by dividing 175.5 by 10.

1 tub = 10 lb

x tubs = \frac{175.5}{10}=17.55=17.5=8\frac{1}{2} tubs

Thus, Richard requires 8\frac{1}{2} tubs of ice cream to sell out on a hot Saturday to make the cones.

Richard requires 8\frac{1}{2} tubs of ice cream to sell out on a hot Saturday to make the cones.

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