Richard works at an ice cream shop. Regular cones get two scoops of ice cream; large cones get three scoops. One hot Saturday, Richard scooped 234 regular cones and 156 large cones. One scoop of ice cream is 3 ounces. A tub of ice cream weighs 10 pounds. How many tubs of ice cream did Richard use to make the cones?
Use the conversion 1 pound = 16 ounces.
Answers
Answer:
The total number of scoops of ice cream that Richard got from the tub is,
(234 regular cones) x (2 scoops / 1 regular cone) + (156 large cones) x (2 scoops / 1 large cone) = 936 scoops
Given that each scoop weighs 3 ounces, the total weight of the ice cream is 2808 ounces. For the number of tubs,
(2808 ounces) x (1 lb / 16 ounces) x (1 tub /10 lb) = 17.55
Thus, the answer is 18.
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Step-by-step explanation:
Given:
No. of scoops for a regular cone = 2
No. of scoops for a large cone = 3
No. of regular cones sold out = 234
No. of large cones sold out = 156
Weight of a tub of ice cream = 10lb
Weight of 1 ice cream scoop = 3oz
To find:
No. of ice cream tubs required by Richard.
Solution:
Richard sells out 234 regular cones which contain 2 scoops each.
Thus, No. of scoops for 234 regular cones = scoops
He also sells out 156 large cones which contain 3 scoops each.
Hence, no. of scoops for 256 large cones = scoops
Total no. of scoops Richard sold = scoops
Given that,
1 scoop = 3oz
1 pound = 16 oz
To convert 936 scoops to required ounces, multiply 936 with 3
∴ 936 scoops = oz
To convert 2808 oz into pounds, divide 2808 by 16
2808 oz = lb
Hence, Richard requires 175.5 lb of ice cream to sell on a hot Saturday.
Also, given that one tub of ice cream weighs 10 lb. Let be the no. of ice cream tubs required by Richard. One tub can contain 10 lb of ice cream, so 175.5 lb of ice cream can contain in no. of tubs which is obtained by dividing 175.5 by 10.
1 tub = 10 lb
tubs = tubs
Thus, Richard requires tubs of ice cream to sell out on a hot Saturday to make the cones.
Richard requires tubs of ice cream to sell out on a hot Saturday to make the cones.