Question

ridhi father 2.5 times as old as ridhi .after 10 years his age will be twice the age of her daughter .find their present ages​

Answer 1

Answer:

let the present age of ridhi (Daughter)= x

then father's present age = 2.5 x

after 10 years scenerio

(2.5x + 10 ) = 2(x+10)

0.5x = 10

x = 20 or age of Daughter is 20

hence age of father will be 50 .(Or 2.5 times of 20)

Answer 2

Answer:

Let Ridhi's present age is = x year

Let Ridhi's father's age is = y year

According to question

y = 2.5*x       ----    equation (a)

After ten years later

ridhi's age will be (x +10)

and his father age will be (y+10)

again, according to question

y+10 = 2(x+10)

y+10=2*x+2*10

y+10 =2x +20

y = 2x +20 -10

y =2x+10     -----  equation (b)

now, from equation (a) & (b)

we have,

2.5x = 2x+10

2.5x-2x =10

0.5x =10

x = 10/0.5 =20

then present age of ridhi is = x= 20 years

and his father's present age is = y =2.5x =2.5*20 =50