Question

Ridhima is five years younger than arav. Four years later arav will be twice as old as Ridhima. Find there present age

Answer 1

Step-by-step explanation:

Given: Ridhima is 5 yrs younger than Aarav.

To find: Their present ages

Solution: Ridhima's age = x

Aarav's age =5x

After 4 yrs,

Aarav's age = 4*5x + 2

Ridhima's age = 4x

20 x + 2 = 4x

20x - 4x = 2

24 X = 2

x = 12

Ridhima's age=12

Aarav's age= 5+12 = 17

Answer 2

Answer:

Ridhima is 1 year old and arav is 6 year old

Step-by-step explanation:

Ridhima is 5 years younger then arav

Ridhima=1

Arav= 6

4 years later =

1 + 4 = 5 {Ridhima}

6 + 4 = 10 {Arav}

So 5 × 2 = 10 .