Question

Rifle of mass 6 kg fires A bullet of mass 20 gram with velocity 57 calculate the initial recoil velocity of the rifle

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

the recoil velocity

$= \frac{ - m1v1}{m2} \\ = \frac{ - 0.02 \times 57}{6} \\ = -0.19$

where=>m1=mass of bullet

M2=mass of rifle

v1=velocity of bullet

the -ve sign indicates that it's direction will be in the opposite to the bullet

Answer 2

Explanation:

the recoil velocity

\begin{lgathered}= \frac{ - m1v1}{m2} \\ = \frac{ - 0.02 \times 57}{6} \\ = -0.19\end{lgathered}

=

m2

−m1v1

=

6

−0.02×57

=−0.19

where=>m1=mass of bullet

M2=mass of rifle

v1=velocity of bullet

the -ve sign indicates that it's direction will be in the opposite to the bullet