Question

Right and prove RHS theorem.

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Answer 1

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$1. : p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

2. \: ( - 5)(z + 2) = - 4 [/tex]

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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Answer 2

RHS Congruence Rule

Theorem: In two right-angled triangles, if the length of the hypotenuse and one side of one triangle, is equal to the length of the hypotenuse and corresponding side of the other triangle, then the two triangles are congruent.