right angle triangle
find bc of abc, ab=5cm,ac=13cm
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∆ABC is right angle at B.
therefore,by Pythagoras theorem,we get
= AC2 = AB2 + BC2
= (13cm)2 = (AB)2 + (5cm)2
= AB2 = (13cm)2 - (5cm)2 = (169-25)
cm2=144cm2
AB = (√144)cm = (√12x12)cm
AB = 12cm
Please write 2up sides of ac,ab and all because I was not having that option ok thanks and your answer is Ab = 12cm
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