Right angle triangle with hypotenuse 53 and perpendicular 15
Answers
Answered by
0
by pythagoras theorem:
H²=P²+B²
(53)²-(15)²=B²
2809-225=B²
2584=B²
B²=√2584
B²=50.833
H²=P²+B²
(53)²-(15)²=B²
2809-225=B²
2584=B²
B²=√2584
B²=50.833
Similar questions