Question

Right angled triangle ∆ pqr , hypotenuse pr = 12 and side pq = 6 , then angle p = ?. *

Answer 1

Answer:

10.39

Step-by-step explanation:

Given : h=12

b=6

To find: p=?

In right angled triangle

We know that

${h}^{2} = {p}^{2} + {b }^{2}$

12*12=p*p+6*6

144=p*p+36

P*p=144-36

P*p=108

P=10.39

Answer 2

Answer:

side1²+side2²=hypotenuse ²

PQ²+QR²=PR²

6²+QR²=12²

QR²=12²-6²=144-36=108

QR=root108 = 6root3=10.39