right-angled triangle △PQR , PQ = 3 cm, PR = 5 cm and QR = 4 cm then show that PQ² + QR² = PR²
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Given : In right-angled triangle △PQR ,
PQ = 3 cm, PR = 5 cm and QR = 4 cm
To find : show that PQ² + QR² = PR²
Solution:
PQ² + QR² = PR²
LHS = PQ² + QR²
PQ = 3 cm
QR = 4 cm
=> LHS = 3² + 4²
=> LHS = 9 + 16
=> LHS = 25
=> LHS = 5²
=> LHS = PR²
=> LHS = RHS
QED
Hence Shown
PQ² + QR² = PR²
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