Question

right angles.
5. A tree is broken at a height of 5 m from the ground
and its top touches the ground at a distance of
12 m from the base of the tree. Find the original
height of the tree for class 7​

Answer 1

$\: \: \: \: \: \: \: \: according \: \: to \: \: question \\ a \: \: right \: angle \: triangle \: is \: formed \\ whose \: height \: and \: base \: are \: 5 m \\ \: and \: 12m \: respectivaly \\ \\ by \: \: phathagores \: \: theorem \\ {hipotenies}^{2} = {base}^{2} + {height}^{2} \\ = > {h}^{2} = {12}^{2} + {5}^{2} \\ = > {h}^{2} = 144 + 25 \\ = > hipotenious = \sqrt{169} = 13m \\ \\ original \: \: height \: \: of \: \: tree \: \: is \: \\ 13 + 5 = > 18m$

Answer 2

Answer:

18m

Step-by-step explanation:

Let ACB be the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ABC is a right angled triangle, at B.

AB = 12 m and BC = 5 m

Using Pythagoras theorem,

In triangle ABC,

$</p><p>{(ac)}^{2} = {(ab)}^{2} + {(bc)}^{2}$

${(ac)}^{2} = {(12)}^{2} + {(5)}^{2}$

${(ac)}^{2} = 144 + 25 = 169$

$ac = \sqrt{169} = 13m$

Hence, the total height of the tree(AB) = AC + CB = 13+ 5 = 18 m.

hope it's helpful