Math, asked by rmbhatt, 7 months ago

Right angles triangles BAC and BDC are right angled at A and D and they are on the same side of BC. If AC and BD intersect at P, then prove that AP.PC = PB.DP. Can someone explain please?

Answers

Answered by mathdude500
1
Please find the attachment
Attachments:
Answered by priyaninandi
0

Answer:

pls show the diagram other wise I can't help u broo

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