Math, asked by sambodhidivitmahipal, 28 days ago

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Find the compound interest on 8000 at 15% for 1 year, if the interest is compounded semi-annually​

Answers

Answered by ushap787
3

Step-by-step explanation:

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Answered by BrainlyTopper97
183

{\large{\boxed{\underline{\mathrm{\bf{\orange{Given:-}}}}}}}

  • Principal = ₹8,000
  • Rate of Interest = 15% per half year
  • Time = 1 year

{\large{\boxed{\underline{\mathrm{\bf{\red{To \ Find:-}}}}}}}

  • Compound Interest, if it is compounded semi-annually.

{\large{\boxed{\underline{\mathrm{\bf{\pink{Formula \ Used:-}}}}}}}

{\pink{\bigstar}} \ {\boxed{\tt{\green{C.I. = P \ \bigg [ \bigg ( 1 + \dfrac{\frac{R}{2}}{100} \bigg )^{ n \times 2} - 1 \bigg ] }}}} \ {\pink{\bigstar}} ------ [semi-annually]

Where,

  • C.I. = Compound Interest
  • P = Principal i.e.  8,000
  • R = Rate i.e. 15%
  • T = Time i.e. 1 year

{\large{\boxed{\underline{\mathrm{\bf{\blue{Solution:-}}}}}}}

Let, the time be n,

Given :-

  • Principal = ₹8,000
  • Rate of Interest = 15% per half year
  • Time = 1 year

According to the question by using the formula of Compound Interest, we get,

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( 1 + \dfrac{\frac{15}{2}}{100} \bigg ) ^{1 \times 2} - 1 \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( 1 + \dfrac{7.5}{100} \bigg ) ^{2} - 1 \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( \dfrac{100 + 7.5}{100} \bigg ) ^{2} - 1 \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( \dfrac{107.5}{100} \times \dfrac{107.5}{100} \bigg ) - 1 \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \dfrac{11,556.25}{10,000} - 1 \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \ \bigg [ \dfrac{11,556.25-100}{10,000} \bigg ] }}

: \ \longmapsto {\mathsf{ \ 8,000 \times \dfrac{11,456.25}{10,000}}}

: \ \longmapsto {\mathsf{ \ 0.8 \times 11,456.25}}

: \ \longmapsto {\mathsf{\bf{ \ 9,165}}}

{\orange{\bigstar}} \ {\underline{\boxed{\mathsf{\green{\therefore Compound \ Interest}{\red{ \ is \ }{\blue{\bf{9,165}}}}}}}} \ {\orange{\bigstar}}

{\huge{\green{\checkmark}}} \ {\large{\boxed{\underline{\mathrm{\bf{\orange{Verification:-}}}}}}} \ {\huge{\green{\checkmark}}}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( 1 + \dfrac{\frac{15}{2}}{100} \bigg ) ^{1 \times 2} - 1 \bigg ]  = 9,165}}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( 1 + \dfrac{7.5}{100} \bigg ) ^{2} - 1 \bigg ] = 9,165}}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( \dfrac{100 + 7.5}{100} \bigg ) ^{2} - 1 \bigg ] =9,165}}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \bigg ( \dfrac{107.5}{100} \times \dfrac{107.5}{100} \bigg ) - 1 \bigg ] = 9,165}}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \dfrac{11,556.25}{10,000} - 1 \bigg ] = 9,165 }}

: \ \mapsto {\mathsf{ \ 8,000 \ \bigg [ \dfrac{11,556.25-100}{10,000} \bigg ] =9,165 }}

: \ \mapsto {\mathsf{ \ 8,000 \times \dfrac{11,456.25}{10,000}=9,165}}

: \ \mapsto {\mathsf{ \ 0.8 \times 11,456.25 = 9,165}}

: \ \mapsto {\mathsf{ \ 9,165 = 9,165}}

\Longrightarrow {\bf{LHS=RHS}} \Longleftarrow

{\mathsf{Hence, Verified}} \ {\large{\green{\checkmark}}}

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