Question

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Answer 1

Answer:

option d)

Explanation:

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Answer 2

a.7.0 degree Clark

1 mole of CaCl

2

≡1 mole of CaCO

3

≡1 mole of MgCl

2

∴ 100mg CaCO

3

is produced by 95mg MgCl

2

∴ 1mg of MgCl

2

gives

95

100

mg CaCO

3

= 1.05mg CaCO

3

Similarly, 1mg of CaCl

2

gives

111

100

mg CaCO

3

= 0.90mg CaCO

3

∴ Total CaCO

3

per litre of water= 1.05+0.90=1.95 mg

Weight of 1000ml of water= 10

3

g=10

6

mg

∴ Total hardness in terms of parts of CaCO

3

per 10

6

parts of water by weight =

10

6

1.95

×10

6

=1.95 ppm

=7.0 Degree Clark [approx]