Math, asked by shourya4141, 1 year ago

right answer will be marked as brainliest

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Answered by JvJvJvJv7777
3

xy = a, xz = b, and yz = c


(xy)(xz) = ab

x^2 = ab/yz = ab/c


(xy)(yz) = ac

y^2 = ac/xz = ac/b


(xz)(yz) = bc

z^2 = bc/xy = bc/a


x^2 - y^2 + z^2 = ab/c - ac/b + bc/a <<< answer


Hope it helps u


Please mark as brainlist answer


Please mark as brainlist answer


shourya4141: wrong answer
Answered by siddhartharao77
2

Given xy = a ---- (1)

Given xz = b ---- (2)

Given yz = c ---- (3)

Multiply (1) & (2), we get

= > x^2yz = ab

= > x^2 = ab/yz

= >x^2 = ab/c ---- (4)

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Multiply (1) & (3), we get

= > xy^2z = ac

= > y^2 = ac/xz

= > y^2 = ac/b ---- (5)

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Multiply (2) & (3), we get

= > xyz^2 = bc

= > z^2 = bc/xy

= > z^2 = bc/a ---- (6)

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So,

From (4),(5),(6),

= > x^2 + y^2 + z^2

= > (ab/c) + (ac/b) + (bc/a).



Hope this helps!


siddhartharao77: :-)
shourya4141: can you explain
siddhartharao77: i already explained
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