Question

Right triangle ABC is shown.

Triangle A B C is shown. Angle A C B is a right angle and angle C B A is 50 degrees. The length of A C is 3 meters, the length of C B is a, and the length of hypotenuse A B is c.

Which equation can be used to solve for c?

sin(50o) = StartFraction 3 Over c EndFraction
sin(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction 3 Over c EndFraction

Answer 1

Sin50°  = 3/c is correct option

Step-by-step explanation:

BC = a

AB = c

AC = 3

Sin = Perpendicular/Hypotenuse

Sin50°  = AC/AB

Sin50°  = 3/c

Cos = Base /Hypotenuse

Cos 50° = BC/AB

=> Cos 50° = a/c

Sin50°  = 3/c is correct option

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Answer 2

Answer:

answer is A, sin(50o) =  3 Over c

I got it right