Question

right triangle pq 5 cm qr 12 cm find pr
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Answer 1

Step-by-step explanation:

In ΔPQR

(PR)2=(PQ)2+(QR)2

(PR)2=(12)2+(5)2

(PR)2=169

PR=13

Now  AOBQ is a square

So, QB=x

Then, BR=5−x

Similarly AQ=x

Then AP=12−x

Also, CR=BR

CR=5−x

[∵ Length of tangents drawn from external point are equal]

And, CP=AP=12−x

[∵ Length of tangents drawn from external point are equal]

PR=PC+CR

13=5−x+12−x

2x=4⇒x=2 cm.