Question

right triangles a base 6 and a hypotenuse 12 what is the second base

Answer 1

by pythagoras theorem

hypo. sq. = side 1^2 + side 2^2

12^2=6^2 + x^2

144=36+x^2

144 - 36 =x^2

108 =x^2

.: side2=√108

.:side 2 =√36 x 3

.:side 2 = 6√3