Math, asked by raviyadav11121314, 1 year ago

rihan land some money to pravin at 10% per annum on 1st January 2012 Praveen feedback 2128 to Rehan on 13 March 2012 what amount did pravin borrow from Rehan​

Answers

Answered by bhagyashreechowdhury
2

If the sum of money lends by Rehan from 1st Jan 2012 to 13th March 2012 at 10% p.a. which amounts to Rs. 2128, then Pravin borrowed Rs. 2087.09 from Rehan.

Step-by-step explanation:

Required formula:

  • S.I. = [PRT]/100
  • A = P + S.I.

Let the sum of money that Pravin borrowed from Rehan be Rs. “P”.

The amount Praveen gave back to Rehan, A = Rs. 2128

The rate of interest, R = 10% p.a.

The time period “T” from 1st Jan 2012 to 13th March 2012 will be,

= 31 + 29 + 12

= 72 days

Since 2012 is a leap year so we will divide by 366 days  

= [72/366] year

= 0.196 year

Now, combining both the above formulas and substituting the given values we get

A – P = [PRT]/100

⇒ 2128 – P = [P*10*0.196]/100

⇒ 212800 – 100P = 1.96P

⇒ 101.96P = 212800

⇒ P = 212800/101.96

P = Rs. 2087.09

Thus, Praveen borrowed Rs. 2087.09 from Rehan.

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