Question

Rind v = 10 y = 5 a=2 2 t=? ​

Answer 1

Answer:

Using tangent secant segments theorem we have

PQ2=PR×PS

⇒(12)2=8×PS

⇒PS=8144=18 units

∴RS=PS−PR=18−8=10 units

Answer 2

Answer:

the formula to calculate the distance between two points (a,b) and (c,d) is given by

dist d = √(a-c)² + (b-d)²

applying it for this ques we have d=10 units

10 = √(2 - 10)² + (-3-y)²

squaring both sides

100 = (-8)² + (9 + y² + 6y)

100 = 64 +9 + y² + 6y

y² + 6y - 27 = 0

y² + 9y - 3y - 27 = 0

y(y + 9) -3(y + 9) = 0

(y-3)(y+9) = 0

y=3 or y=-9

both values of y are possible unless no other condition is specified in the question.