Question

Ring is fixed on the horizontal surface and a
rod starts rotating with constant angular
velocity 'o' fixed at 'O' as shown in the figure.
Find the magnitude of velocity of intersection
point of rod and ring when a becomes 90°.
(A) VR2-2r26
(B) VR2-26
Ro
(C)
2
P
C->
(D) RO​

Answer 1

Answer:

(D)

Explanation:

Velocity of points A which lie on road =rω

Here angular velocity= o

So velocity of intersection points vcosθ= ro

⇒v=(r.oRr)/r

So, v= Ro

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