ring of radius 0.5 metre and
kg 10 kg is rotating about its diameter angular velocity of 20 Radian per second its kinetic energy is
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Answer:
Data
radius = 0.5 m
mass = 10kg
angular velocity = 20 rad/sec
Solution.
Step 1
V =rw (w = angular velocity)
V =0.5×20
V = 10 m/s (V = linear velocity)
Step 2
K.E = 1/2mV²
= 1/2×10×100
K.E = 500 J.
Hope you get it clearly!
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