Question

Rishabh has borrowed Rs. 4000 at the rate of 7% S.I. what amount he needs to pay after 3 years to clear the debt?​

Answer 1

$\dag \; {\underline{\boxed{\pmb{\orange{\frak{ \; Given \; :- }}}}}}$

• Principal = Rs.4000
• Rate = 7 %
• Time = 3 years

$\dag \; {\underline{\boxed{\pmb{\purple{\frak{ \; To \; Find \; :- }}}}}}$

• Amount = ?

$\dag \; {\underline{\boxed{\pmb{\red{\frak{ \; SolutioN \; :- }}}}}}$

$\maltese$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ S.I = \dfrac{ P \times R \times T }{100} }}}}}$

• ${\underline{\boxed{\pmb{\sf{ Amount = Principal + S.I }}}}}$

Where :

• S.I = Simple Interest
• R = Rate
• T = Time
• P = Principal

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$\maltese$ Calculating the Simple Interest :

$\begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ P \times R \times T }{100} } \\ \end{gathered}$

$\begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 7 \times 3 }{100} } \\ \end{gathered}$

$\begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 21 }{100} } \\ \end{gathered}$

$\begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{84000}{100} } \\ \end{gathered}$

$\begin{gathered} \longmapsto \; \; \sf { S.I = \cancel\dfrac{84000}{100} } \\ \end{gathered}$

$\begin{gathered} \longmapsto \; \; {\underline{\underline{\pmb{\pink{\sf{ Simple \; Interst = ₹ \; 840 }}}}}} \end{gathered}$

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$\maltese$ Calculating the Amount :

$\begin{gathered} \dashrightarrow \; \; \sf { Amount = Principal + Simple \; Interst } \\ \end{gathered}$

$\begin{gathered} \dashrightarrow \; \; \sf { Amount = 4000 + 840 } \\ \end{gathered}$

$\begin{gathered} \dashrightarrow \; \; {\underline{\underline{\pmb{\green{\sf{ Amount = ₹ \; 4840 }}}}}} \end{gathered}$

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$\maltese$ Therefore :

❛❛ Rishabh had to pay ₹ 4840 to clear the debt . ❜❜

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