Question

rishav is twice as old as sonu five years ago he's age was three times sonu's age find their present ages?

Answer 1

Let present age of sonu is x years and age of rishav is twice of age sonu which is 2x years,

Given that before 5 years, age of rishav was thrice the age of sonu,

5 years ago, age of sonu = present age( in years ) - 5 years = ( x - 5 ) years

5 years ago, age of rishav = present age ( in years ) - 5 years = ( 2x - 5 ) years

Age of rishav before 5 years = 3 × age of suno before 5 years

=>> ( 2x - 5 ) = 3( x - 5 )

=>> 2x - 5 = 3x - 15

=>> 15 - 5 = 3x - 2x

$\boxed{ \bold{ x = 1 0 }}$

Hence,

Present age of sonu = x years = 10 years

Present age of rishav = 2x years = 2( 10 years ) = 20 years

Answer 2

Let present age of Sonu be X years.


Present age of Rishav = 2X year's.



Five years ago age of Sonu = ( X - 5 ) years.


Five years ago age of Rishav = ( 2X - 5 ) years.


According to the question,






3 ( X - 5 ) = 2X - 5


3X - 15 = 2X - 5



3X - 2X = -5 + 15



X = 10 years.



Present age of Sonu = X = 10 years.

And,


Present age of Rishav = 2X = 20 years.