Rishi makes a cuboid of sides 5 cm, 2 cm & 5 cm. How many such cuboids will he need to form the smallest cube?
Explain with complete calculations & justifications.
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Answered by
4
HAI FRIEND, I WILL TRY TO EXPLAIN WHAT I KNOW
PLEASE MARK IT AS BRAINLIEST, PLEASE FOLLOW
let
length of smallest cube side be 10 because LCM of sides is 10
volume of cube =10^3
=1000
dimensions of cuboid =5*2*5
volume of cuboid =50
no. of cuboids =1000/50
=20
there fore 20 cubes are required to form
the smallest cube
PLEASE MARK IT AS BRAINLIEST, PLEASE FOLLOW
let
length of smallest cube side be 10 because LCM of sides is 10
volume of cube =10^3
=1000
dimensions of cuboid =5*2*5
volume of cuboid =50
no. of cuboids =1000/50
=20
there fore 20 cubes are required to form
the smallest cube
Anonymous:
corrected
Answered by
2
side of smallest cuboid = LCM of {5,2,5}
= 10 cm
so volume of cube = (a)^3 = (10)^3
= 1000 cm^3
length of cuboid (l)= 5 cm
breadth of cuboid(b)= 2cm
height of cuboid (h)= 5 cm
volume of cuboid =l×b×h
=5×2×5= 50 cm^3
let number of cube required be "n"
so volume of "n" cubes = n×50
so according to question..
=) n×50 = 1000
=) n = 1000/50 = 20 cubes
so number of cubes required = 20ans..
hope it helps...
= 10 cm
so volume of cube = (a)^3 = (10)^3
= 1000 cm^3
length of cuboid (l)= 5 cm
breadth of cuboid(b)= 2cm
height of cuboid (h)= 5 cm
volume of cuboid =l×b×h
=5×2×5= 50 cm^3
let number of cube required be "n"
so volume of "n" cubes = n×50
so according to question..
=) n×50 = 1000
=) n = 1000/50 = 20 cubes
so number of cubes required = 20ans..
hope it helps...
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