rishikant, during his journey, travels for 20 minutes at a speed of 30 km/h, another 30 minutes at a speed of 50 km/h, and 1 hour at a speed of 50 km/h and 1 hour at a speed of 60 km/h. what is the average speed ?
Answers
Answered by
32
At first, he travels for 20 mins or 1/3 hr at 30 km/hr
So, distance traveled is = speed x time
d1 = 30 x 1/3
d1 = 10 km
After, he travels for 30mins or 1/2 hr at 50 km/hr
d2 = 50 x 1/2
d2 = 25 km
After, he travels for 1 hr at 50 km/hr
d3 = 50 x 1
d3 = 50 km
Finally, he travels for 1 hr at 60 km/hr
d4 = 60 x 1
d4 = 60 km
Avg speed = Total dist / total time
Total dist d = d1 + d2 + d3 + d4
d = 10 + 25 + 50 + 60
d = 145 km
Total time = 1/3 + 1/2 + 1 + 1
= 2/6 + 3/6 + 6/6 + 6/6
= 17/6 hr
Avg speed = 145 / (17/6)
= 145 * 6 / 17
= 51.18 km/hr
So, distance traveled is = speed x time
d1 = 30 x 1/3
d1 = 10 km
After, he travels for 30mins or 1/2 hr at 50 km/hr
d2 = 50 x 1/2
d2 = 25 km
After, he travels for 1 hr at 50 km/hr
d3 = 50 x 1
d3 = 50 km
Finally, he travels for 1 hr at 60 km/hr
d4 = 60 x 1
d4 = 60 km
Avg speed = Total dist / total time
Total dist d = d1 + d2 + d3 + d4
d = 10 + 25 + 50 + 60
d = 145 km
Total time = 1/3 + 1/2 + 1 + 1
= 2/6 + 3/6 + 6/6 + 6/6
= 17/6 hr
Avg speed = 145 / (17/6)
= 145 * 6 / 17
= 51.18 km/hr
Answered by
5
Answer:
At first, he travels for 20 mins or 1/3 hr at 30 km/hr
So, distance traveled is = speed x time
d1 = 30 x 1/3
d1 = 10 km
After, he travels for 30mins or 1/2 hr at 50 km/hr
d2 = 50 x 1/2
d2 = 25 km
After, he travels for 1 hr at 50 km/hr
d3 = 50 x 1
d3 = 50 km
Finally, he travels for 1 hr at 60 km/hr
d4 = 60 x 1
d4 = 60 km
Average speed = Total dist / total time
Total dist d = d1 + d2 + d3 + d4
d = 10 + 25 + 50 + 60
d = 145 km
Total time = 1/3 + 1/2 + 1+1
= 2/6 + 3/6 + 6/6 + 6/6
= 17/6 hr
Avg speed = 145 / (17/6)
= 145 * 6/ 17
= 51.18 km/hr
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