Rita accelerates a 0.4 00 kg ball from rest to 9 .00 m/s during the 0.15 0 s in which her foot is in co ntact with the ball. What average force does she apply to the ball during the kick?
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v = u + at
a = ( v - u ) / t
a = 9 / 0.15
a = 60 m/s^2
F = ma
F = 0.4 × 60
F = 24.0 N
a = ( v - u ) / t
a = 9 / 0.15
a = 60 m/s^2
F = ma
F = 0.4 × 60
F = 24.0 N
Answered by
2
Given,
Mass of the ball = 0.4 kg
Initial velocity(u) = 0 m/s
Final velocity(v) = 9 m/s
Time taken = 0.15 s
To Find,
The average force applied by Rita during the kick.
Solution,
By using the equation of motion
v = u + a*t
9 = 0+a(0.15)
a = 9/0.15
a = 60 m/s²
Now,
Force = mass*acceleration
So,
F = 0.4*60
F = 24 N
Hence, the average force applied by Rita to the ball during the kick is 24 N.
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