Question

Rita lent a sum of ₹ 400 at the rate of 6% per annum . Find how much interest she received after 3 years .

Answer 1

Step-by-step explanation:

Principal =Rs 400 rate =6% per annum

Time =3 years

SI=principal ×rate×time /100

=400×6×3/100=72

Ans:The interest she received after 3 years is Rs 72

Answer 2

Answer :

➥ The interest she received after 3 years = Rs. 72

Given :

➤ Principal (P) = Rs. 400

➤ Rate (R) = 6%

➤ Time (T) = 3 years

To Find :

➤ Interest she received after 3 years (S.I) = ?

Solution :

As we know that

$\tt{:\implies S.I = \dfrac{P \times R \times T}{100}}$

$\tt{:\implies S.I = \dfrac{400 \times 6 \times 3 }{100}}$

$\tt{:\implies S.I = \dfrac{2400 \times 3}{100}}$

$\tt{:\implies S.I = \dfrac{72 \cancel{00}}{1 \cancel{00}}}$

$\tt{:\implies S.I = \dfrac{72}{1}}$

$\bf{:\implies \underline{ \: \: \underline{ \red{ \: \: S.I = Rs. 72 \: \: }} \: \: }}$

║ Hence, the interest she received after 3 years is Rs. 72 ║

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Some related formulae :

⪼ $\sf{S.I = \dfrac{P \times R \times T}{100}}$

⪼ $\sf{P = 100 \times \dfrac{S.I}{R \times T}}$

⪼ $\sf{T = 100 \times \dfrac{S.I}{R \times P}}$

⪼ A = P + SI

Where,

• S.I is the Simplest Interest.
• P is the Principal.
• R is the Rate.
• T is the Time.
• A is the Amount.

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