Math, asked by chefaviral3610, 1 year ago

Rites sold 2 jeans for Rs. 990 each. He gains 10 percent on 1st and loses 10 percent on 2nd .What is his gain or loss percent ?

Answers

Answered by Anonymous
0
Selling Price of lst jeans = ₹990
Gain = 10 %
Cost Price = SP × 100/100+gain%
= 990×100/100+10
= 99,000/110
= ₹900
Selling Price of 2nd jeans = ₹990
Loss = 10 %
Cost Price = SP × 100/100-loss%
= 990×100/100-10
= 99,000/90
= ₹1,100
Total Cost Price of both jeans = ₹(900+1,100) = ₹2,000
Total Selling Price of both jeans = ₹(990×2) = ₹1,980
Loss = Cost Price - Selling Price
= ₹(2,000-1,980)
= ₹20
Loss % = Loss/CP × 100
= 20/2,000 ×100
= 1%


Hope it helps you.
What regards@
Tanisha
Answered by mysticd
0
Hi ,

1 ) selling price first jeans = Rs 990

s.p = Rs 990

Loss ( l ) = 10%

Cost price = c.p

c.p = ( s.p × 100 ) / ( 100 - l )

= ( 990 × 100 ) / ( 100 - 10 )

= 99000 / 90

= 1100

c.p = Rs 1100

2 ) selling price of second jeans

= Rs 990

Gain ( g ) = 10 %

c.p = ( s.p × 100 ) / ( 100 + g )

= ( 990 × 100 ) / ( 100 + 10 )

= 99000 / 110

= 900

c.p = Rs 900

3 ) s.p of two jeans = 990 + 990

Total s.p = Rs 1980

Total c.p = 1100 + 900 = Rs 2000

Therefore ,

Total c.p > total s.p

He gets loss.

Loss = total c.p - total s.p

= 2000 - 1980

= Rs 20
Loss% = ( loss × 100 ) / ( total c.p )

= ( 20× 100 ) / 2000

= 1 %

I hope this helps you.

:)
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