Ritesh had a sum of 34350. He invested a part of it for 2 years at simple interest at the rate of 8% p.a. and the rest for 4 years at simple interest at 8.5% p.a. If he earned total interest of 9204, find the sum he invested at each rate.
I will mark the most explained and detailed answer as brainliest
20 marks for solving
Class 7
Simple Interest
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Answers
Answered by
17
Here is your answer.
Let the Sum is x
invested in 2 years and 8% p.a
and
in II CASE
Sum = 34350 - x
invested in 4 years ,8.5%
Now. I Case
As we know the formula
SI = PRT/100
Now II case
SI = PRT/100
ATQ
TOTAL INTEREST IS 9204
So Other part is
= 34350 - 13750
= 20600
Therefore he invested is 13750 and 20600
MonarkSingh:
Thanks for the brainliest
Answered by
9
Here is your answer
Let Sum is x and other is 34350-x
ATQ
![\frac{x \times 8 \times 2}{100} + (34350 - x) \times \frac{8.5 \times 4}{100} = 9204 \\ \frac{4x}{25} + (34350 - x) \times \frac{8.5}{25} = 9204 \\ on \: solving \\ x = 13750 \\ \\ other \: is \\ 34350 - 13750 \\ = 20600 \frac{x \times 8 \times 2}{100} + (34350 - x) \times \frac{8.5 \times 4}{100} = 9204 \\ \frac{4x}{25} + (34350 - x) \times \frac{8.5}{25} = 9204 \\ on \: solving \\ x = 13750 \\ \\ other \: is \\ 34350 - 13750 \\ = 20600](https://tex.z-dn.net/?f=+%5Cfrac%7Bx+%5Ctimes+8+%5Ctimes+2%7D%7B100%7D++%2B+%2834350+-+x%29+%5Ctimes++%5Cfrac%7B8.5+%5Ctimes+4%7D%7B100%7D++%3D+9204+%5C%5C++%5Cfrac%7B4x%7D%7B25%7D++%2B+%2834350+-+x%29+%5Ctimes++%5Cfrac%7B8.5%7D%7B25%7D++%3D+9204+%5C%5C+on+%5C%3A+solving+%5C%5C+x+%3D+13750+%5C%5C++%5C%5C+other+%5C%3A+is+%5C%5C+34350+-+13750+%5C%5C++%3D+20600)
So he Invested
Rs 13750 and 20600
Thanks
Let Sum is x and other is 34350-x
ATQ
So he Invested
Rs 13750 and 20600
Thanks
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