Ritesh went to a shopping mall to buy a trouser costing Rs. 3500 . On his request , shopkeeper allowed two successive discounts of x% and y% (x > y) . if Ritesh paid Rs. 2618 including sales tax 10%. then discount rates given by shopkeeper are ___ and ___ respectively.
Answers
||✪✪ QUESTION ✪✪||
Ritesh went to a shopping mall to buy a trouser costing Rs. 3500 . On his request , shopkeeper allowed two successive discounts of x% and y% (x > y) . if Ritesh paid Rs. 2618 including sales tax 10%. then discount rates given by shopkeeper are ___ and ___ respectively ? (Nice Question ).
|| ✰✰ ANSWER ✰✰ ||
let the reduced price of the dress be Rs.x
→ sales tax on rs.x=(x×10/100)=x/10
So,
→ amount paid by Ritesh = (x+x/10)=11/10x
A.T.Q
→ (11/10x) = 2618
→ x = (10/11) × 2618 = 2380
so, The reduced price After Two Discount is = Rs.2380 ..
______________________
Now, it is given that, cost of trouser was 3500 and shopkeeper allowed two successive discounts of x% and y% ..
So,
→ 3500 * [ (100 - x)/100 ] * [ (100-y)/100 ] = 2380
→ 35(100-x)(100-y) = 238000
Dividing both sides by 35, we get,
→ (100-x)(100-y) = 6800
Now, If we have Options we can solve it Easily, but Since option are not their , we can use Hit and Trial now, or , Lets make Factors of 6800 .
→ (100-x)(100-y) = (16 * 5 )* (17 * 5 )
→ (100-x)(100-y) = 80 * 85 ( As x > y)
So,
→ 100-x = 80
→ x = 20% .
And,
→ (100-y) = 85
→ y = 15% .
Hence, Discount rates given by shopkeeper are 20% and 15% respectively.
QUESTION :-
Ritesh went to a shopping mall to buy a trouser costing Rs. 3500 . On his request , shopkeeper allowed two successive discounts of x% and y% (x > y) . if Ritesh paid Rs. 2618 including sales tax 10%. then discount rates given by shopkeeper are ___ and ___ respectively ?
ANSWER :-
let the reduced price of the dress be Rs.100
→ sales tax on rs.100=(100×10/100) = 10
→ amount paid by Ritesh = 110
Given,
→ 110= 2618
→ 100 = (100/110) × 2618 = 2380
The reduced price After Two Discount is = Rs.2380 ..
Now given that cost of trouser was 3500 and shopkeeper allowed two successive discounts of x% and y% ..
using SP = MP*(100-D)/100 = SP
=> 3500 * [ (100 - x)/100 ] * [ (100-y)/100 ] = 2380
=> 35(100-x)(100-y) = 238000
=> (100-x)(100-y) = 6800
=> (100-x)(100-y) = (16 * 5 )* (17 * 5 )
=> (100-x)(100-y) = 80 * 85 ( As x > y)
putting now,
100-x = 80
x = 20% .
(100-y) = 85