Math, asked by bhatigirinandini, 1 day ago

Ritish bought 2 Kg less onions in Rs 55 due to an increase in price of onions by 12%. What was the increased price of onions per Kg? Also find the original pace of the onions . ​

Answers

Answered by Laraleorapathi
0

Step-by-step explanation:

Let the original weight he bought be x kg

Price of one kg of onion = 55 / x

New weight = (x - 2) kg

New price of one kg of onion = 55 / (x-2)

It is given that price increased by 12%

This implies that new price of one kg of onion = 112 / 100 of original price of one kg of onion

55 / (x-2) = 112 /100 × 55/x

=> 55 / (x-2) = 6160 / 100x

=> 55 × 100x = 6160 (x-2)

=> 5500x = 6160x - 12320

=> 5500x - 6160x = -12320

=> 660x = 12320

=> x = 12320 / 660

=> x = 18.66

______________________________

ANSWER =

ORIGINAL PRICE OF ONION = 55 / 18.66

= Rs. 2.94 OR Approx. Rs. 3

______________________________

Answered by jeon36491
14

Answer:

Let the original weight he bought be x kg

Price of one kg of onion = 55 / x

New weight = (x - 2) kg

New price of one kg of onion = 55 / (x-2)

It is given that price increased by 12%

This implies that new price of one kg of onion = 112 / 100 of original price of one kg of onion

55 / (x-2) = 112 /100 × 55/x

=> 55 / (x-2) = 6160 / 100x

=> 55 × 100x = 6160 (x-2)

=> 5500x = 6160x - 12320

=> 5500x - 6160x = -12320

=> 660x = 12320

=> x = 12320 / 660

=> x = 18.66

______________________________

ANSWER =

ORIGINAL PRICE OF ONION = 55 / 18.66

= Rs. 2.94 OR Approx. Rs. 3

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