Math, asked by anuskhabhujel722, 2 months ago

Ritu bought a saree for ₹60x and sold it for₹(500+4x) at a loss of x%. Find the cost price​

Answers

Answered by aarthi1312002
0

Step-by-step explanation:

SOLUTION

The cost price of saree = Rs. 60x

and selling price = Rs. (500 + 4x)

Loss = x%

Now according to the condition

S.P. = C.P. x 100-Loss%100 / 100

500 + 4x = 60x(100-x)/100

⇒ 50000 + 400x = 6000x - 60x2

⇒ 60x2 - 6000x + 400x + 50000 = 0

⇒ 60x2 - 5600x + 50000 = 0

⇒ 3x2 - 280x + 2500 = 0 ...(Dividing by 20)

⇒ 3x2 - 30x - 250x + 2500 = 0

⇒ 3x(x - 10) - 250(x - 10) = 0

⇒ (x - 10)(3x - 250) = 0

Either x - 10 = 0,

then x = 10

or

3x - 250 = 0,

then 3x = 250

⇒ x = 250/3

But it is not possible

∴ Loss = 10%

Cost price = 60x

= 60 x 10

= Rs. 600.

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