Math, asked by asthajain26, 10 months ago

Ritu brought a saree for Rs. 60x and sold it for Rs. ( 500+4x ) at a loss of x% . Find the cost price .​

plzz ans it fast

Answers

Answered by shlokolsh
1

Answer:

The original price is 535.2

Step-by-step explanation:

60x - (500 + 4x) = x%

56x = 500

x = 500/56

8.92

60 x 8.92

= 535.2

Hope this helps!

Answered by chinnuchiranthan5
0

Answer:

c p=60*83.33=4999.8 (appro) 5000

Step-by-step explanation:

c p=60 x

s p=500+4 x

loss=60 x-500-4 x=56 x-500

loss%=loss/c p*100

x=56 x-500/60 x*100

60 x^2=5600 x-50000

dividing by 20

3 x^2=280 x-2500

3 x^2-280 x+2500=0

3 x^2-30 x-250 x+2500=0

3 x(x-10)-250(x-10)=0

3 x-250=0 or x-10=0

x=250/3=83.333 or 10

so c p=60*83.33 as if x value is 10 then the sp would be 740

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