Math, asked by pranjal032153, 16 hours ago

RITU FINISHED COLOURING A PICTURE IN 7/12 HOUR. REEMA FINISHED
COLOURINGE THE SAME PICTURE IN 3/12 HOUR.WHO WORKED LONGER? BY
WHAT FRACTION WAS IT LONGER?

Answers

Answered by Manjula29
1

Let's consider the whole work takes X hours to be finished

Ritu finished the colouring by X.7/12 = 7X/ 12 hour

Reema finished the same colouring  by X.3/12= 3X/12hour

therefore

Ritu takes 7X hours to finishe the colouring

Reema takes 3X hours to finish the same task.

therefore Ritu takes more time than Reema, as number 7 is bigger than 3.

Ans: Ritu worked longer, so 7/12 fraction is longer.

Answered by amitnrw
0

Given : RITU FINISHED COLOURING A PICTURE IN 7/12 HOUR.

REEMA FINISHED COLOURINGE THE SAME PICTURE IN 3/12 HOUR

To Find: Who worked longer

and how much longer

Solution:

Ritu worked for 7/12  hrs

Reema worked for 3/12 hrs

Denominator is same in both case

so directly comparing numerator

7 > 3

=> 7/12 > 3/12

Hence Ritu  worked longer

7/12 - 3/12

= ( 7 - 3)/12

= 4/12

= 1/3   hrs

Ritu worked 4/12 or 1/3 hrs longer than Reema

Learn More:

Write the fractions and pair up the equivalent fractions from each row

brainly.in/question/5451929

find the equivalent fraction of 56/70 with (I) numerator 4 (ii ...

brainly.in/question/12231577

Similar questions