Physics, asked by subhash2255, 10 months ago


River is flowing with velocity (3i+2j)m/s. A boat
is moving in river with velocity (3i-2j) m/s with respect to
the river. The speed of boat w.r.t ground is
(1) 1 m/s
(2) 4 m/s
(3) 6 m/s
(4) 8 m/s

please answer this question. ..its urgent (step by step answer please )​

Answers

Answered by soorajs1289
1

Answer:

4

Explanation:

I am not sure

relative velocity of boat with river=Vbr

3i-2j-(3i+2j)

so -3i get cancelled

=-4j

taking modulus root of (-4^2)=root 16

which is=4

Answered by AneesKakar
0

The speed of the boat with respect to the ground is equal to 6 m/s.

Given:

The velocity of the river with respect to the ground (V_{RG}) = (3i + 2j) m/s

The velocity of the boat with respect to the river (V_{BR} ) = (3i - 2j) m/s

To Find:

The magnitude of the speed of boat with respect to the ground.

Solution:

→ Let the velocity of the boat with respect to the ground be V_{BG}

→ If the velocity of an object A with respect to the ground is V_{AG} and the velocity of an object B with respect to the ground is V_{BG}, then the relative velocity of B with respect to A is given by:

             \therefore Velocity\:of\:B\:with\:respect\:to\:A\:(V_{BA} ) = V_{BG} -V_{AG}

→ The velocity of the boat with respect to the river that is V_{BR} would be given by:

      \therefore Velocity\:of\:Boat\:with\:respect\:to\:River\:(V_{BR} ) = V_{BG} -V_{RG}

                                    \therefore V_{BR}  = V_{BG} -V_{RG}\\\\\therefore V_{BG} =V_{BR} +V_{RG}\\\\\:{\boldsymbol{\therefore V_{BG} =[(3)\hat{\textbf{\i}}}} -(2)\hat{\textbf{\j}}}}]\: + \:[(3)\hat{\textbf{\i}}}} +\:{\boldsymbol{(2)\hat{\textbf{\j}}}}]\\\\{\boldsymbol{\therefore V_{BG}=(6)\hat{\textbf{\i}}}

Therefore it can be said that the speed of the boat with respect to the ground is equal to 6 m/s.

#SPJ2

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