Question

River of width 100 m flows from left to right, at
5 ms-1. A swimmer capable of swimming at
4 ms-1 in still water, wants to cross the river
through swimming. His minimum drift can be
(1) 90 m
(2) 100 m
(3) 75 m
(4) 50 m​

Answer 1

hey guy here is your answer

here we will apply minimum time approach

t= d/V(still water) = 100/4 = 25 s

drift is given by D= V(river)*t

                             = 5*25 = 125 m  

hope it helps

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