Question

Riya bought 3 bottles for rs 250 each.He sold a bottle at a loss of 10% and earn 16 % profit on whole bottle

Answer 1

The complete question is:

Riya bought 3 bottles for Rs. 250 each. She sold a bottle at 10% loss. To earn 16% profit on whole deal, at what% profit should the remaining bottles be sold?

Solution:

Given, cost of each bottle = Rs. 250

Then the cost of 3 bottles is

= Rs. 3 * 250 = Rs. 750

One bottle is sold at 10% loss, then its selling price is

= Rs. 250 (1 - 10/100) = Rs. 225

Let, each of the remaining bottles be sold at Rs. X each to earn 16% profit on all the 3 bottles.

16% profit

= Rs. 750 (1 + 16/100) = Rs. 870

ATQ, 2X + 225 = 870

or, 2X = 870 - 225 = 645

or, X = 322.50

So each of the remaining bottles is to be sold at Rs. 322.50

Hence, profit% on the selling price of each of the remaining 2 bottles should be

= [{(selling price / cost price) * 100} - 100] %

= {(322.50 * 100 / 250) - 100} %

= (129 - 100) %

= 29%

Answer 2

Answer:

Step-by-step explanation:

In this question,

We have been given that

Riya bought 3 bottles for Rs.250 each

He sold a bottle at a loss of 10%

We need to find the at what % remaining bottles should be sold to earn a total profit of 16%

Total cost of 3 bottles = 250 × 3

                                     = Rs.750

Riya sold a bottle at 10% loss then,

We know that

%Loss = $\mathbf{\frac{Loss}{Cost\ Price}\times 100}$

Here Loss% = 10;  Cost price = 250

Putting the values we get,

10 = $\frac{loss}{250}\times 100}$

Loss = Rs.25

Selling Price = Cost price - Loss

Selling Price = 250 - 25

Selling price = Rs.225

Now, We know that,

Cost Price = $\mathbf{\frac{100}{100\ +\ gain \%}\times Selling\ Price}$

Here, Cost price = 750 Gain% = 16%

Putting the values we get,

Cost Price = $\frac{100}{100\ +\ 16}\times Selling\ Price$

750 = $\frac{100}{116}\times Selling\ price$

87000 = 100 × Selling Price

Selling price = Rs.870

Therefore Selling Price of all the 3 bottles should be Rs.870

But one bottle has been sold at Rs.225

Therefore, 2 bottles need to be sold at = 870 - 225

                                                                 = Rs.645

Cost price of 2 bottles = 250 × 2

Cost price of 2 bottles = Rs.500

Cost Price = $\mathbf{\frac{100}{100\ +\ gain \%}\times Selling\ price}$

Here Cost price = Rs.500  Selling Price = Rs 645

Putting the values we get,

500 = $\frac{100}{100\ +\ gain \%}\times 645$

$\frac{500}{645}\ =\ \frac{100}{100\ +\ Gain \%}$

On solving we get,

Gain% = 29%

Remaining bottle needs to be sold at 29%