Question

Riya Didi report krdiye questions!​

Answer 1

Answer:

Let No. of coins be x We are given, x + x / 2 = 300; =3x/2=300 so, x = 200 So, there are 200 50p coins as well as 200 1 rupee coins.let the number of 50 paisa coin = n let the number of 1 rupee coin = n; 50paisa = x 1 \ \ pee=y now, nx + ny = 300; n(x + y) = 300; n(y / 2 + y) = 300; n(3y / 2) = 300(asx = y / 2); n = 300 * 2 / 3 (putting y=1); n = 200 ANSWERStep-by-step explanation:

We are given that two sides of triangular field are 85 M and 154 m

Perimeter of triangle = 324 M

Let the third side be x

Perimeter of triangle =Sum of all sides

$\Rightarrow85+154+x </p><p>$

$\Rightarrow239+x$

Since we are given that Perimeter of triangle = 324M;

$So, \Rightarrow 324 = 239 +x;</p><p>$

$\Rightarrow324 - 239 = x; \\ </p><p> </p><p> \Rightarrow8 5 = x \\ </p><p>$

Now we will use heron's formula to find the area of triangle

$\rightarrow \: a = 85m \\ </p><p> \rightarrow \: b = 154m; \\ </p><p> \rightarrow \: c = 85m; \\ </p><p> </p><p>Area = \sqrt{(s(s - a) \times (s - b) \times (s - c))} ; \\ \\ s \rightarrow\frac{ (a + b + c)}{2}$

Substitute the values:

$\rightarrow \: s = \frac{(85 + 154 + 85)}{2} \\ \\ \\ \\ </p><p></p><p></p><p>\Rightarrow s = 162; \\ \\ \\ \\ </p><p> </p><p>\Rightarrow \: Area =; \sqrt{162(162-85)(162-154)(162-85)} ;</p><p>$

${\boxed{ \green {\Rightarrow \: Area = 2772}}}$

So, Area of triangle is 2772

Now rto find the length of the perpendicular from the opposite vertex on the site measuring 154 m

$Area = \frac{1}{2} \times B a s e \times H e i g h t;$

2772 = 1/2 ×154 ×H e i g h t;

(2772 ×2)/154 = Height;

36 = Height

Hence Area of triangle is 2772 and he length of the perpendicular from the opposite vertex on the site measuring 154 m is 36 m