Riya got 80% of 200 marks in English,82%of200 in Computer Science and 60% of 100 in Hindi. If the total pass percentage is 40%, did she pass or fail?
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Answered by
27
Here is your answer
Riya got
English = 80% of 200 =80x200/100 =160
Computer science = 82% of 200
= 82x 200/100 = 164
Hindi = 60% of 100. = 60x 100/100. = 60
Hence Riya got 160 +164 +60 = 384
Total marks = 200 +200 +100 =500
percentage = 384 x 100/500
= 76.8%
Hence she passed.
Hope it helps you.
Riya got
English = 80% of 200 =80x200/100 =160
Computer science = 82% of 200
= 82x 200/100 = 164
Hindi = 60% of 100. = 60x 100/100. = 60
Hence Riya got 160 +164 +60 = 384
Total marks = 200 +200 +100 =500
percentage = 384 x 100/500
= 76.8%
Hence she passed.
Hope it helps you.
Answered by
2
Step-by-step explanation:
80×200/100=160,
82×200/100=164,
60×100/100=60,
40×500/100=200
Pass
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