Question

Riya has 5 rupees more than 4 times the amount with Ritu. If each is given 25

rupees more, then the ratio of their amount is 9 : 4, find how many rupees Ritu

originally had???
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Answer 1

Answer:

20/7

Step-by-step explanation:

riya =x and ritu=y

x+5=4y

x=4y-5

x/y=9/4=4y-5/y

9y=16y-20

7y=20

Answer 2

AnswEr :

Here we're given that, Riya had Rs 5 more than 4 times the amount of Ritu. Moreover we're also provided with ratio of amt. they had. Also, they both were given some Amt. of money & we've to find how many rupees did Ritu had with her!

Let's assume that Ritu had overall Rs x.

According to the question,

Total amount Riya has = Rs 4x + 5

Also, if both were given additional Rs 25,

• Amt. Riya had = 4x + 30

• Amt. Ritu had = x + 25

We're given their ratio as 9 : 4 respectively !

Equating,

$\longrightarrow$ 4x + 30/x + 25 = 9/4

$\longrightarrow$ 4(4x +b30) = 9(x + 25)

$\longrightarrow$ 16x + 120 = 9x + 225

$\longrightarrow$ 16x - 9x = 225 - 120

$\longrightarrow$ 7x = 105

$\therefore$ x = 15

Hence, Ritu had Rs 15 originally.