Riya spent 3/5 of her money on handbag. She spent rest of the money on a dress and a belt. the handbag costs twice as much as the dress. the dress cost rupees 20 more than the belt. how much money did she gave in the beginning?
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Total Cost=Rs x
Handbag cost (H)=3/5x
Cost of Dress (D)+ Belt (B)=x-3/5x=2/5x ie D+B=2/5x---(1)
Handbag Cost=2 D
Dress Cost= 20+ Belt (B) ie D=20+B ie D-B=20---(2)
Handbag cost (H)=3/5x=2D
D+B=2/5x---(1)
D-B=20---(2)
Add equation 1 & equation 2
D+B + D-B=2/5x+20
2D=2/5x+20
3/5x=2/5x+20 (substituting 2D=3/5X)
3/5x-2/5x=20
x/5=20
x=100
total cost riya had in the beginning =Rs 100
Handbag cost (H)=3/5x=3/5x100=Rs 60
Dress Cost = Rs 30
Belt Cost=Rs 10
Handbag cost (H)=3/5x
Cost of Dress (D)+ Belt (B)=x-3/5x=2/5x ie D+B=2/5x---(1)
Handbag Cost=2 D
Dress Cost= 20+ Belt (B) ie D=20+B ie D-B=20---(2)
Handbag cost (H)=3/5x=2D
D+B=2/5x---(1)
D-B=20---(2)
Add equation 1 & equation 2
D+B + D-B=2/5x+20
2D=2/5x+20
3/5x=2/5x+20 (substituting 2D=3/5X)
3/5x-2/5x=20
x/5=20
x=100
total cost riya had in the beginning =Rs 100
Handbag cost (H)=3/5x=3/5x100=Rs 60
Dress Cost = Rs 30
Belt Cost=Rs 10
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