Riya was facing some difficulty in simplifying 5 √7 − √3 . Her classmate Tom gave her a clue to rationalise the denominator. Riya simplified the expression and thanked Tom for his goodwill.
i) The rationalizing factor of √7 − √3 is: Options a. √7 + √3 b. √7 − √3 c. 7 – 3 d. 7 + 3
ii) The sum of a rational number and an irrational number is: a. rational b. irrational c. natural number d. zero
iii) The identity used by Riya to solve the denominator is a. (a + b)2 b. (a – b)2 c. (a + b) (a – b) d. (x + a) (x + b)
iv) After simplifying Riya got the denominator as: a. - 3 b. -4 c. 3 d. 4
v) What answer did Riya get after simplification: a. 5(√7+√3) 4 b. 5(√7 − √3) 4 c. − 5(√7+√3) 4 d. − 5(√7 − √3) 4
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