Math, asked by sidhusingh, 1 year ago

riyaz mother is seven times older than him. four years from now, she will be four times as old as riyaz will then be. what are their present ages

Answers

Answered by seherran
71
let riyaz age b x
mothers age=7x
4 yrs later:
riyaz age=x+4
mother age=7x+4
a/q
7x+4=4(x+4)
7x+4=4x+16
7x-4x=16-4
3x=12
x=4
therefore, riyaz age=4
mothers age=7(4)=28
Answered by miliranjana19
0

Answer:

riyaz's Age = x

his mother's age = 7x

after 4 years,

riyaz's age will be = x + 4

his mother's age = 7x + 4 or 4x +4

therefore a/q,

7x+4=4(x+4)

7x+4=4x+16

7x-4x=16-4

3x = 12

x = 12/3

x = 4

then,

4*7+4

28+4

32

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