riyaz mother is seven times older than him. four years from now, she will be four times as old as riyaz will then be. what are their present ages
Answers
Answered by
71
let riyaz age b x
mothers age=7x
4 yrs later:
riyaz age=x+4
mother age=7x+4
a/q
7x+4=4(x+4)
7x+4=4x+16
7x-4x=16-4
3x=12
x=4
therefore, riyaz age=4
mothers age=7(4)=28
mothers age=7x
4 yrs later:
riyaz age=x+4
mother age=7x+4
a/q
7x+4=4(x+4)
7x+4=4x+16
7x-4x=16-4
3x=12
x=4
therefore, riyaz age=4
mothers age=7(4)=28
Answered by
0
Answer:
riyaz's Age = x
his mother's age = 7x
after 4 years,
riyaz's age will be = x + 4
his mother's age = 7x + 4 or 4x +4
therefore a/q,
7x+4=4(x+4)
7x+4=4x+16
7x-4x=16-4
3x = 12
x = 12/3
x = 4
then,
4*7+4
28+4
32
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