Question

Riyaz's mother is seven times older than him. Four years from now,she will be four times as old as riyaz will then be . What are their present ages??
I WILL LIKE AND FOLLOW
WITH EXPLANATION PLEASE​.

Answer 1

Answer:

let riyaz age b x

mothers age=7x

4 yrs later:

riyaz age=x+4

mother age=7x+4

a/q

7x+4=4(x+4)

7x+4=4x+16

7x-4x=16-4

3x=12

x=4

therefore, riyaz age=4

mothers age=7(4)=28

Answer 2

Answer:

let x be mothers age and y be riyaz's age.

Then

x = 7y

After 4 years,

[x+4] = 4[y+4] => x - 4y = 12

Solving the 2 equations,

=> y = 4 = riyaz's age

& x = 28 = mothers age

may it help u