Question

∆RKN ~∆SPV In ∆RKN ,RK = 6.4cm ,R=60°,K = 50°and RN /SV =4/3 then construct ∆RKN ~∆Spv ​

Answer 1

$\huge \fbox \purple{❥ Answer}$

Given : ∆RKN similar ∆SPV

In ∆RKN,RK=6.4 angle K=50 ANGLE R=60 and RN/SV=4/3

To Find :  construct Triangles

Solution:

Step 1 : Draw a line segment RK = 6.4  unit

Step 2 : Draw an angle of 60° at R on KR using protractor

Step 3 : Draw an angle of 50° at K on RK using protractor

Step 4 : Mark intersection of angles as  N

∆RKN is constructed.

∆RKN similar ∆SPV

RN/ SV = 4/3

=> RK/SP = 4/3

=> SP = 3RK/4

=> SP = 3(6.4)/4

=> SP = 4.8

∠S = ∠R = 60°

∠P = ∠K = 50°

Step 1 : Draw a line segment SP = 4.8  unit

Step 2 : Draw an angle of 60° at S on PS using protractor

Step 3 : Draw an angle of 50° at P on SP using protractor

Step 4 : Mark intersection of angles as  V

∆SPV is constructed.

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Answer 2

Answer:

It will be easy to understanad.