Question

∆RKN ~∆SPV in ∆ RSK ,RK =6.4 cm ,R= 60°,k= 50° and rn/sv= 4/5 then construct ∆ RKN ~∆SPV.
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Answer 1

$\huge \fbox \purple{❥ Answer}$

Given that △RST∼△UAY:

In △RST,RS=6 cm,∠S=50∘,ST=7.5 cm

Given that the corresponding sides of △RST and △UAY are in the ratio 5:4.

∴UARS=UYST=UYRT=45

∠S=∠A=50∘

∴UARS=45

∴UA6=45

∴UA=56×4

∴U=4.8 cm

Similarly, AYST=45

AY7.5=45

∴AY=57.5×4

∴AY=6 cm.

Therefore, in △UAY,UA=4.8 cm,AY=6 cm and ∠A=50∘